Question
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
Stats
| Frequency | 1 |
| Difficulty | 1 |
| Adjusted Difficulty | 1 |
| Time to use | -------- |
Ratings/Color = 1(white) 2(lime) 3(yellow) 4/5(red)
Solution
This is a easy question.
My code
public class Solution {
public int lengthOfLastWord(String s) {
if (s == null || s.length() == 0) {
return 0;
}
int p = s.length() - 1;
while (p >= 0 && s.charAt(p) == ' ') {
p--;
}
if (p == -1) {
return 0;
}
int q = p;
while (q >= 0 && s.charAt(q) != ' ') {
q--;
}
return p - q;
}
}