Question
Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given 1->2->3->4->5->NULL
and k = 2
,
return 4->5->1->2->3->NULL
.
Stats
Frequency | 2 |
Difficulty | 3 |
Adjusted Difficulty | 3 |
Time to use | -------- |
Ratings/Color = 1(white) 2(lime) 3(yellow) 4/5(red)
Solution
This is a very basic question, but not very easy.
The implementation is a lot of node operations. The rest of things is straight-forward.
Read this blog for more.
My code
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode rotateRight(ListNode head, int n) {
if (head == null) {
return null;
}
ListNode p = head;
for (int i = 0; i < n; i++) {
if (p.next != null) {
p = p.next;
} else {
p = head;
}
}
ListNode q = head;
while (p.next != null) {
p = p.next;
q = q.next;
}
if (q.next == null) {
return head;
}
ListNode newHead = q.next;
q.next = null;
p.next = head;
return newHead;
}
}