Question

link

Given a sorted set, find if there exist three elements in Arithmetic Progression or not.

Solution

This is a rather simple Arithmetic Progression question.

To find the three elements, we first fix an element as middle element and search for other two (one smaller and one greater).

O(n²) time.

Code

written by me

public boolean longest(int[] A) {
    int len = A.length;
    for (int i = 1; i < len - 1; i++) {
        int left = i - 1;
        int right = i + 1;
        while (left >= 0 && right < len) {
            int total = A[left] + A[right];
            if (total > 2 * A[i]) {
                left--;
            } else if (total < 2 * A[i]) {
                right++;
            } else {
                return true;
            }
        }
    }
    return false;
}